(x^2+5)+(x-1)=

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Solution for (x^2+5)+(x-1)= equation:


Simplifying
(x2 + 5) + (x + -1) = 0

Reorder the terms:
(5 + x2) + (x + -1) = 0

Remove parenthesis around (5 + x2)
5 + x2 + (x + -1) = 0

Reorder the terms:
5 + x2 + (-1 + x) = 0

Remove parenthesis around (-1 + x)
5 + x2 + -1 + x = 0

Reorder the terms:
5 + -1 + x + x2 = 0

Combine like terms: 5 + -1 = 4
4 + x + x2 = 0

Solving
4 + x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-4' to each side of the equation.
4 + x + -4 + x2 = 0 + -4

Reorder the terms:
4 + -4 + x + x2 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + x + x2 = 0 + -4
x + x2 = 0 + -4

Combine like terms: 0 + -4 = -4
x + x2 = -4

The x term is x.  Take half its coefficient (0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
x + 0.25 + x2 = -4 + 0.25

Reorder the terms:
0.25 + x + x2 = -4 + 0.25

Combine like terms: -4 + 0.25 = -3.75
0.25 + x + x2 = -3.75

Factor a perfect square on the left side:
(x + 0.5)(x + 0.5) = -3.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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